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Linear Systems Help –?


i need som help
4x + y = 0 - (1)
x + 2y +1 = 0 - (2)
this what im doing
put eq (2) into eq (1)
x = -2y -1
4(-2y -1) = 0
8y - + y - 8 = 0
9y = 8
y = 8/9
im lost after this help?

By admin | category: EQ | tags: , , |

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One Response to 'Linear Systems Help –?'

  1. minx - July 9th, 2010 at 4:45 pm

    Multiply (2) by 4 to lose the x’s
    4x + y = 0
    4x + 8y + 4 = 0 Take one away from the other
    4x + y ……..= 0 -
    ___________
    …….7y + 4 = 0
    ……7y = - 4
    y = - 4/7
    therefore 4x = 4/7
    x = 1/7
    Check in (2)
    1/7 - 8/7 + 1 = 0
    x = 1/7 and y = - 4/7
    If you do it your way
    x = - 2y -1
    4 ( - 2y - 1) + y = 0
    - 8y - 4 +y = 0
    - 7y = 4
    - y = 4/7
    y = - 4/7
    Sub for y in (1)
    4x - 4/7 = 0
    4x = 4/7
    x = 1/7


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